Role in dependence graphs

AI-generated audit

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Audited against the exact journal version of record

Not a correctness certificate. These reports do not replace expert scrutiny or formal verification.

Exact reviewed source

Annals of Mathematics version of record

Dzmitry Badziahin, Andrew Pollington, and Sanju Velani. On a problem in simultaneous Diophantine approximation: Schmidt's conjecture. Annals of Mathematics 174 (2011), no. 3, 1837–1883.

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Generated August 27, 2026
01Statements1 reported findingNo statement issues found

The selected rational-line lemma is correct and is stronger than the baby lemma imported by An16.

Lemma 1No issue found

The weighted rational line has the asserted coefficient bounds

VOR pp. 1854–1855 · Lemma 1

For each rational point P=(p/q,r/q)P=(p/q,r/q), Lemma 1 constructs a primitive integer line through PP with ∣A∣≤qi|A|\le q^i and 0<B≤qj0<B\le q^j under its additional slice hypothesis. The first construction already yields the weaker nonzero-(A,B)(A,B) form needed by An16 and Wu–Yang without that hypothesis.

02Proofs1 reported findingNo proof issues found

The selected portion is an elementary, complete pigeonhole argument.

Proof of Lemma 1No issue found in the reviewed proof

Equal residues in the weighted box produce the required line

VOR pp. 1854–1855

There are more integer pairs in the prescribed weighted rectangle than residue values of ap−brap-br modulo qq. Subtracting two pairs with equal residue gives Ap−Br+Cq=0Ap-Br+Cq=0 with the printed bounds and (A,B)≠(0,0)(A,B)\ne(0,0). The later badly-approximable-coordinate argument only rules out B=0B=0 and is irrelevant to the recursive edge.

03Novelty0 reported findingsNo novelty concerns found

No non-novelty findings.

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