arXiv:1806.05989v1
Abstract
For real we consider irrationality measure function . We prove that in the case there exist arbitrary large values of with . This result is optimal.
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Not a correctness certificate. A “Correct” result may include yellow typos or minor formal corrections that do not affect substantive soundness. It means this audit found no unresolved substantive error under the stated criteria; it does not replace expert scrutiny or formal verification.
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Detailed mathematical audit
01Statements2 reported findingsCorrect
The optimal constant in the comparison of two irrationality-measure functions is correct.
The lower comparison occurs arbitrarily far out and the constant is sharp
Pages 2–6 · Theorems 1–2 and their proofs · arXiv:1806.05989v1
The interlacing of the two convergent-denominator sequences forces one of the adjacent approximation remainders to differ by the golden-ratio threshold. The periodic extremal pattern realizes equality asymptotically, so no larger universal constant can replace it.
Full paper, version 1 ↗A minimum and one remainder symbol are typos
Pages 2–3 · Auxiliary Lemma 1 · arXiv:1806.05989v1
Part (iii) requires the maximum of the two displayed quantities, as used in the corollary and proof, not their minimum. In the second symmetric line, the remainder belonging to beta is , not a second . Both corrections are forced by the stated exchange of alpha and beta.
02Proofs2 reported findingsCorrect
The continued-fraction case analysis and sharpness example are complete after the two auxiliary-lemma symbol corrections.
The constructed interlacing pattern proves sharpness
Pages 5–6 · Section 4 and proof of Theorem 2 · arXiv:1806.05989v1
The recursively chosen partial quotients make the two denominator sequences alternate in the prescribed pattern, while their adjacent remainder ratios converge to the golden ratio . Consequently the normalized difference of the two irrationality-measure functions approaches from the admissible side at every possible comparison point. This rules out any larger universal constant.
The golden-ratio dichotomy and extremal example close
Pages 2–6 · auxiliary lemmas and proofs · arXiv:1806.05989v1
The corrected maximum makes the dichotomy exhaustive, and the recurrence relations translate it directly into the comparison of the two step functions. The constructed interlacing sequence approaches the threshold from the allowed side, proving optimality.
03Novelty0 reported findingsNo non-novelty findings
No non-novelty findings.